Exact expanded PA statement
forall p h a. p = 2 * h + 1 -> p = 4 * a + 1 -> h = 2 * aStructural proof guide
Generated structural guide
The half of a fixed odd number congruent to one modulo four is exactly even.
Use the direct prerequisites four_mul_eq_double_double, odd_half_unique as previously established PA formulas.
The proof proceeds by intermediate claims (1).
Referenced ingredients
Proof neighborhood
Direct dependencies
Direct dependents
Formal native tactic body
Dependencies are introduced as named hypotheses before line 1. Linked names are exact direct references. This Alpha-v16 checked-use theorem is independently kernel-checked when replayed; it is not a Stable theorem.
- 0001
intro p - 0002
intro h - 0003
intro a - 0004
intro hp - 0005
intro hfour - 0006
have hcanonical : p = 2 * (2 * a) + 1 - 0007
trans 4 * a + 1 - 0008
exact hfour - 0009
congr - 0010
apply four_mul_eq_double_double - 0011
refl - 0012
specialize odd_half_unique p - 0013
specialize odd_half_unique h - 0014
specialize odd_half_unique (2 * a) - 0015
apply odd_half_unique - 0016
exact hp - 0017
exact hcanonical